C++ Exercises: Find Disarium numbers between 1 to 1000

C++ Numbers: Exercise-19 with Solution

Write a program in C++ to find Disarium numbers between 1 to 1000.

Pictorial Presentation:

Sample Solution:

C++ Code :

  #include<bits/stdc++.h>
using namespace std;
 
int DigiCount(int n)
{
    int ctr_digi = 0;
    int tmpx = n;
    while (tmpx)
    {
        tmpx = tmpx/10;
 
        ctr_digi++;
    }
    return ctr_digi;
}
bool chkDisarum(int n)
{
    int ctr_digi = DigiCount(n);
    int s = 0; 
    int x = n;
    int pr;
    while (x)
    {
        pr = x % 10;
        s = s + pow(pr, ctr_digi--);
        x = x/10;
    }
    return (s == n);
}
int main()
{

int i;
 cout << "\n\n Find Disarium Numbers between 1 to 1000: \n";
 cout << " ---------------------------------------------\n";
 cout << " The Disarium numbers are: "<<endl;
for(i=1;i<=1000;i++)
{
    if( chkDisarum(i))
	cout <<i<<" "; 
}	
	cout <<endl;
}

Sample Output:

 Find Disarium Numbers between 1 to 1000:                                                            
 ---------------------------------------------                                                       
 The Disarium numbers are:                                                                           
1 2 3 4 5 6 7 8 9 89 135 175 518 598

Flowchart:

C++ Code Editor:

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