C++ Exercises: Display the n terms of odd natural number and their sum

C++ For Loop: Exercise-20 with Solution

Write a program in C++ to display the n terms of odd natural number and their sum.

Pictorial Presentation:

Sample Solution:-

C++ Code :

#include <iostream>
using namespace std;

int main()
{
    int i, n, sum = 0;

    cout << "\n\n Display n terms of odd natural number and their sum:\n";
    cout << "---------------------------------------------------------\n";
    cout << " Input number of terms: ";
    cin >> n;
    cout << " The odd numbers are: ";
    for (i = 1; i <= n; i++) 
    {
        cout << 2 * i - 1 << " ";
        sum += 2 * i - 1;
    }
    cout << "\n The Sum of odd Natural Numbers upto " << n << " terms"; 

" << sum << endl";
}

Sample Output:

Display n terms of odd natural number and their sum:                  
---------------------------------------------------------              
 Input number of terms: 5                                              
 The odd numbers are: 1 3 5 7 9 

Flowchart:

C++ Code Editor:

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