C++ Exercises: Find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n

C++ For Loop: Exercise-11 with Solution

Write a program in C++ to find the sum of the series 1 + 1/2^2 + 1/3^3 + …..+ 1/n^n.

Pictorial Presentation:

Sample Solution :-

C++ Code :

#include <iostream>
#include <math.h>
using namespace std;

int main()
{
    double sum = 0, a;
    int n, i;
    cout << "\n\n Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n:\n";
    cout << "----------------------------------------------------------------\n";
    cout << " Input the value for nth term: ";
    cin >> n;
    for (i = 1; i <= n; ++i) 
	{
        a = 1 / pow(i, i);
        cout << "1/" << i << "^" << i << " = " << a << endl;
        sum += a;
    }
    cout << " The sum of the above series is: " << sum << endl;
}

Sample Output:

 Find the sum of the series 1 + 1/2^2 + 1/3^3 +.....+ 1/n^n:           
----------------------------------------------------------------       
 Input the value for nth term: 5                                       
1/1^1 = 1                                                              
1/2^2 = 0.25                                                           
1/3^3 = 0.037037                                                       
1/4^4 = 0.00390625                                                     
1/5^5 = 0.00032                                                        
 The sum of the above series is: 1.29126  

Flowchart:

C++ Code Editor:

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