C++ Exercises: Check two given integers and return the value whichever value is nearest to 13 without going over
C++ Basic Algorithm: Exercise-55 with Solution
Write a C++ program to check two given integers and return the value whichever value is nearest to 13 without going over. Return 0 if both numbers go over.
Sample Solution:
C++ Code :
#include <iostream>
using namespace std;
int test(int x, int y)
{
if (x > 13 && y > 13) return 0;
if (x <= 13 && y > 13) return x;
if (y <= 13 && x > 13) return y;
return x > y ? x : y;
}
int main()
{
cout << test(4, 5) << endl;
cout << test(7, 12) << endl;
cout << test(10, 13) << endl;
cout << test(17, 33) << endl;
return 0;
}
Sample Output:
5 12 13 0
Pictorial Presentation:
Flowchart:
C++ Code Editor:
Contribute your code and comments through Disqus.
Previous: Write a C++ program to compute the sum of the three given integers. However, if any of the values is in the range 10..20 inclusive then that value counts as 0, except 13 and 17.
Next: Write a C++ program to check three given integers (small, medium and large) and return true if the difference between small and medium and the difference between medium and large is same.
What is the difficulty level of this exercise?