C++ Exercises: Compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x
C++ Basic Algorithm: Exercise-51 with Solution
Write a C++ program to compute the sum of two given non-negative integers x and y as long as the sum has the same number of digits as x. If the sum has more digits than x then return x without y.
Sample Solution:
C++ Code :
#include <iostream>
#include<string>
using namespace std;
int test(int x, int y)
{
return to_string(x + y).length() > to_string(x).length() ? x : x + y;
}
int main()
{
cout << test(4, 5) << endl;
cout << test(7, 4) << endl;
cout << test(10, 10) << endl;
return 0;
}
Sample Output:
9 7 20
Pictorial Presentation:
Flowchart:
C++ Code Editor:
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