C++ Exercises: Count the number of two 5's are next to each other in an array of integers
C++ Basic Algorithm: Exercise-35 with Solution
Write a C++ program to count the number of two 5's are next to each other in an array of integers. Also count the situation where the second 5 is actually a 6.
Sample Solution:
C++ Code :
#include <iostream>
using namespace std;
int test(int numbers[], int arr_length)
{
int ctr = 0;
for (int i = 0; i < arr_length; i++)
{
if ((numbers[i]==5 && (numbers[i + 1]==5 )) || ( numbers[i]==5 && (numbers[i + 1]==6))) ctr++;
}
return ctr;
}
int main()
{
int arr_length;
int nums1[] = {5, 5, 2};
arr_length = sizeof(nums1) / sizeof(nums1[0]);
cout << test(nums1, arr_length) << endl;
int nums2[] = {5, 5, 2, 5, 5};
arr_length = sizeof(nums2) / sizeof(nums2[0]);
cout << test(nums2, arr_length) << endl;
int nums3[] = {5, 6, 2, 9};
arr_length = sizeof(nums3) / sizeof(nums3[0]);
cout << test(nums3, arr_length) << endl;
return 0;
}
Sample Output:
1 2 1
Pictorial Presentation:
Flowchart:
C++ Code Editor:
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