C++ Exercises: Check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array

C++ Basic Algorithm: Exercise-114 with Solution

Write a C++ program to check a given array of integers and return true if the specified number of same elements appears at the start and end of the given array.

Sample Solution:

C++ Code :

#include <iostream>

using namespace std;

static bool test(int numbers[], int arr_length, int n)
        {
            
            for (int i = 0; i < n; i++)
            {
                if (numbers[i] != numbers[arr_length - n + i])
                {
                    return false;
                }
            }

            return true;
          }   
          
int main() 
 {  
  int nums1[] = {3, 7, 5, 5, 3, 7 };
  int n = 2;
  int arr_length = sizeof(nums1) / sizeof(nums1[0]);
  cout << test(nums1, arr_length, n) << endl; 
  int nums2[] = {3, 7, 5, 5, 3, 7};
  n = 3;
  arr_length = sizeof(nums2) / sizeof(nums2[0]);
  cout << test(nums2, arr_length, n) << endl;
  int nums3[] = {3, 7, 5, 5, 3, 7, 5};
  n = 3;
  arr_length = sizeof(nums3) / sizeof(nums3[0]);
  cout << test(nums3, arr_length, n) << endl;
  return 0;    
}

Sample Output:

1
0
1

Pictorial Presentation:

Flowchart:

C++ Code Editor:

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