C++ Exercises: Check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other
C++ Basic Algorithm: Exercise-111 with Solution
Write a C++ program to check a given array of integers and return true if the given array contains either 2 even or 2 odd values all next to each other.
Sample Solution:
C++ Code :
#include <iostream>
using namespace std;
static bool test(int numbers[], int arr_length)
{
int tot_odd = 0, tot_even = 0;
for (int i = 0; i < arr_length; i++)
{
if (tot_odd < 2 && tot_even < 2)
{
if (numbers[i] % 2 == 0)
{
tot_even++;
tot_odd = 0;
}
else
{
tot_odd++;
tot_even = 0;
}
}
}
return tot_odd == 2 || tot_even == 2;
}
int main()
{
int nums1[] = {3, 5, 1, 3, 7};
int arr_length = sizeof(nums1) / sizeof(nums1[0]);
cout << test(nums1, arr_length) << endl;
int nums2[] = {1, 2, 3, 4};
arr_length = sizeof(nums2) / sizeof(nums2[0]);
cout << test(nums2, arr_length) << endl;
int nums3[] = {3, 3, 5, 5, 5, 5};
arr_length = sizeof(nums3) / sizeof(nums3[0]);
cout << test(nums3, arr_length) << endl;
int nums4[] = {2, 4, 5, 6};
arr_length = sizeof(nums4) / sizeof(nums4[0]);
cout << test(nums4, arr_length) << endl;
return 0;
}
Sample Output:
1 0 1 1
Pictorial Presentation:
Flowchart:
C++ Code Editor:
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