C++ Exercises: Count the number of occurrences of given number in a sorted array of integers

C++ Array: Exercise-20 with Solution

Write a C++ program to count the number of occurrences of given number in a sorted array of integers.

Pictorial Presentation:

Sample Solution:

C++ Code :

#include <iostream>
using namespace std;

int count_occurrences(int arr[], int n, int x)
{
    int result = 0;
    for (int i=0; i<n; i++)
        if (x == arr[i])
          result++;
    return result;
}
 
int main()
{
    int nums[] = {5, 7, 8, 8, 5, 8, 7, 7}; 
    int n = sizeof(nums)/sizeof(nums[0]);
    cout << "Original array: ";
    for (int i=0; i < n; i++) 
    cout << nums[i] <<" ";
    int x = 7;
    cout <<"\nNumber of occurrences of 7 : " << count_occurrences(nums, n, x);
    return 0;
    }

Sample Output:

Original array: 5 7 8 8 5 8 7 7 
Number of occurrences of 7 : 3

Flowchart:

C++ Code Editor:

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