C Exercises: Demonstrate the working of keyword long
C Variable Type : Exercise-18 with Solution
Write a C program to demonstrate the working of keyword long.
Sample Solution:
C Code:
#include<stdio.h>
int main()
{
int a;
long b;
long long c;
double e;
long double f;
printf("\n Demonstrate the working of keyword long \n");
printf("------------------------------------------\n");
printf(" The size of int = %ld bytes \n", sizeof(a));
printf(" The size of long = %ld bytes\n", sizeof(b));
printf(" The size of long long = %ld bytes\n", sizeof(c));
printf(" The size of double = %ld bytes\n", sizeof(e));
printf(" The size of long double = %ld bytes\n\n", sizeof(f));
return 0;
}
Sample Output:
Demonstrate the working of keyword long ------------------------------------------ The size of int = 4 bytes The size of long = 8 bytes The size of long long = 8 bytes The size of double = 8 bytes The size of long double = 16 bytes
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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