C Programming: Count of each character in a given string

C String: Exercise-33 with Solution

Write a C programming to count of each character in a given string.

Sample Solution:

C Code:

#include<stdio.h>
#include<string.h>
int if_char_exists(char c, char p[],  int x, int y[])
{
	int i;
	for (i=0; i<=x;i++)
	{
		if (p[i]==c)
		{
		y[i]++;
		return (1);
		}
	}
	if(i>x) return (0);
}
int main()
{
	char str1[80],chr[80];
	int n,i,x,ctr[80];
	printf("Enter a str1ing: ");
	scanf("%s",str1);
	n=strlen(str1);
	chr[0]=str1[0];
	ctr[0]=1;
	x=0;
	for(i=1;i < n;  i++)
	{
		if(!if_char_exists(str1[i], chr, x, ctr))
		{	
			x++;		
			chr[x]=str1[i];
			ctr[x]=1;
		}
	}
	printf("The count of each character in the string %s is \n", str1);
	for (i=0;i<=x;i++)
		printf("%c\t%d\n",chr[i],ctr[i]);
}

Sample Output:

 Enter a str1ing: The count of each character in the string w3resource is 
w	1
3	1
r	2
e	2
s	1
o	1
u	1
c	1 

Flowchart :

C Programming Code Editor:

Improve this sample solution and post your code through Disqus.

Previous: Write a C programming to find the repeated character in a given string.
Next: Write a C programming to convert vowels into upper case character in a given string.