C Programming: Count the number of punctuation characters exists in a string

C String: Exercise-26 with Solution

Write a program in C to count the number of punctuation characters exists in a string.

Sample Solution:

C Code:

#include<stdio.h>
#include<ctype.h>

int main()
{
	int ctr1=0;
	int ctr2=0;
	char str[100]; 
	printf("\n Count the number of punctuation characters exists in a string :\n");  
    printf("------------------------------------------------------------------\n");	
    printf(" Input a string : ");
	fgets(str, sizeof str, stdin); 	
	while (str[ctr1])
	{
		if (ispunct(str[ctr1])) ctr2++;
		ctr1++;
	}
	printf (" The punctuation characters exists in the string is : %d\n\n", ctr2);
  	return 0;
}

Sample Output:

 Count the number of punctuation characters exists in a string :
------------------------------------------------------------------
 Input a string : The quick brown fox,jumps over the,lazy dog.
 The punctuation characters exists in the string is : 3

Flowchart :

C Programming Code Editor:

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