C Programming: Concatenate Two Strings Manually
C String: Exercise-19 with Solution
Write a program in C to Concatenate Two Strings Manually.
Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
void main()
{
char str1[100], str2[100], i, j,l,m,k;
printf("\n\nConcatenate Two Strings Manually :\n");
printf("-------------------------------------\n");
printf("Input the first string : ");
fgets(str1,sizeof str1,stdin);
printf("Input the second string : ");
fgets(str2,sizeof str2,stdin);
l=strlen(str1);
m=strlen(str2);
for(i=0; i<l-1; ++i); /* value i contains reaches the end of string str1. */
str1[i]=' '; /* add a space with string str1. */
i++; /* value i increase by 1 for the blank space */
for(j=0; j<m-1; ++j, ++i)
{
str1[i]=str2[j];
}
k=strlen(str1);
printf("After concatenation the string is : \n ");
for(i=0; i<k; ++i)
{
printf("%c",str1[i]);
}
printf("\n\n");
}
Sample Output:
Concatenate Two Strings Manually : ------------------------------------- Input the first string : this is string one Input the second string : this is string two After concatenation the string is : this is string one this is string two
Flowchart :
C Programming Code Editor:
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Next: Write a program in C to find the largest and smallest word in a string.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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