C Programming: Sorts the strings of an array using bubble sort
C String: Exercise-12 with Solution
Write a program in C to read a string through keyboard and sort it using bubble sort.
Sample Solution:
C Code:
#include <stdio.h>
#include <string.h>
void main()
{
char name[25][50],temp[25];
int n,i,j;
printf("\n\nSorts the strings of an array using bubble sort :\n");
printf("-----------------------------------------------------\n");
printf("Input number of strings :");
scanf("%d",&n);
printf("Input string %d :\n",n);
for(i=0;i<=n;i++)
{
fgets(name[i], sizeof name, stdin);
}
/*Logic Bubble Sort*/
for(i=1;i<=n;i++)
for(j=0;j<=n-i;j++)
if(strcmp(name[j],name[j+1])>0)
{
strcpy(temp,name[j]);
strcpy(name[j],name[j+1]);
strcpy(name[j+1],temp);
}
printf("The strings appears after sorting :\n");
for(i=0;i<=n;i++)
printf("%s\n",name[i]);
}
Sample Output:
Sorts the strings of an array using bubble sort : ----------------------------------------------------- Input number of strings :3 Input string 3 : zero one two The strings appears after sorting : one two zero
Flowchart :
C Programming Code Editor:
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Next: Write a program in C to extract a substring from a given string.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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