C Exercises: Find the first missing positive integer from a given unsorted integer array

C Programming Practice: Exercise-27 with Solution

In the 20×20 grid below, four numbers along a diagonal line have been marked in red.
08 02 22 97 38 15 00 40 00 75 04 05 07 78 52 12 50 77 91 08
49 49 99 40 17 81 18 57 60 87 17 40 98 43 69 48 04 56 62 00
81 49 31 73 55 79 14 29 93 71 40 67 53 88 30 03 49 13 36 65
52 70 95 23 04 60 11 42 69 24 68 56 01 32 56 71 37 02 36 91
22 31 16 71 51 67 63 89 41 92 36 54 22 40 40 28 66 33 13 80
24 47 32 60 99 03 45 02 44 75 33 53 78 36 84 20 35 17 12 50
32 98 81 28 64 23 67 10 26 38 40 67 59 54 70 66 18 38 64 70
67 26 20 68 02 62 12 20 95 63 94 39 63 08 40 91 66 49 94 21
24 55 58 05 66 73 99 26 97 17 78 78 96 83 14 88 34 89 63 72
21 36 23 09 75 00 76 44 20 45 35 14 00 61 33 97 34 31 33 95
78 17 53 28 22 75 31 67 15 94 03 80 04 62 16 14 09 53 56 92
16 39 05 42 96 35 31 47 55 58 88 24 00 17 54 24 36 29 85 57
86 56 00 48 35 71 89 07 05 44 44 37 44 60 21 58 51 54 17 58
19 80 81 68 05 94 47 69 28 73 92 13 86 52 17 77 04 89 55 40
04 52 08 83 97 35 99 16 07 97 57 32 16 26 26 79 33 27 98 66
88 36 68 87 57 62 20 72 03 46 33 67 46 55 12 32 63 93 53 69
04 42 16 73 38 25 39 11 24 94 72 18 08 46 29 32 40 62 76 36
20 69 36 41 72 30 23 88 34 62 99 69 82 67 59 85 74 04 36 16
20 73 35 29 78 31 90 01 74 31 49 71 48 86 81 16 23 57 05 54
01 70 54 71 83 51 54 69 16 92 33 48 61 43 52 01 89 19 67 48
The product of these numbers is 26 × 63 × 78 × 14 = 1788696.
Write a C programming to find the greatest product of four adjacent numbers in the same direction (up, down, left, right, or diagonally) in the 20×20 grid.

C Code:

// (c) 2009, eagletmt  MIT License <https://opensource.org/licenses/mit-license.php>
#include <stdio.h>
#define N 20
static __inline unsigned max(unsigned a, unsigned b);

int main(void)
{
  unsigned grid[20][20] = {
    {8,2,22,97,38,15,0,40,0,75,4,5,7,78,52,12,50,77,91,8},
    {49,49,99,40,17,81,18,57,60,87,17,40,98,43,69,48,4,56,62,0},
    {81,49,31,73,55,79,14,29,93,71,40,67,53,88,30,3,49,13,36,65},
    {52,70,95,23,4,60,11,42,69,24,68,56,1,32,56,71,37,2,36,91},
    {22,31,16,71,51,67,63,89,41,92,36,54,22,40,40,28,66,33,13,80},
    {24,47,32,60,99,3,45,2,44,75,33,53,78,36,84,20,35,17,12,50},
    {32,98,81,28,64,23,67,10,26,38,40,67,59,54,70,66,18,38,64,70},
    {67,26,20,68,2,62,12,20,95,63,94,39,63,8,40,91,66,49,94,21},
    {24,55,58,5,66,73,99,26,97,17,78,78,96,83,14,88,34,89,63,72},
    {21,36,23,9,75,0,76,44,20,45,35,14,0,61,33,97,34,31,33,95},
    {78,17,53,28,22,75,31,67,15,94,3,80,4,62,16,14,9,53,56,92},
    {16,39,5,42,96,35,31,47,55,58,88,24,0,17,54,24,36,29,85,57},
    {86,56,0,48,35,71,89,7,5,44,44,37,44,60,21,58,51,54,17,58},
    {19,80,81,68,5,94,47,69,28,73,92,13,86,52,17,77,4,89,55,40},
    {4,52,8,83,97,35,99,16,7,97,57,32,16,26,26,79,33,27,98,66},
    {88,36,68,87,57,62,20,72,3,46,33,67,46,55,12,32,63,93,53,69},
    {4,42,16,73,38,25,39,11,24,94,72,18,8,46,29,32,40,62,76,36},
    {20,69,36,41,72,30,23,88,34,62,99,69,82,67,59,85,74,4,36,16},
    {20,73,35,29,78,31,90,1,74,31,49,71,48,86,81,16,23,57,5,54},
    {1,70,54,71,83,51,54,69,16,92,33,48,61,43,52,1,89,19,67,48},
  };
  unsigned m = 0;
  unsigned i, j;

  for (i = 0; i < N-3; i++) {
    for (j = 0; j < N-3; j++) {
      unsigned h = grid[i][j] * grid[i][j+1] * grid[i][j+2] * grid[i][j+3];
      unsigned v = grid[j][i] * grid[j+1][i] * grid[j+2][i] * grid[j+3][i];
      unsigned d1 = grid[i][j] * grid[i+1][j+1] * grid[i+2][j+2] * grid[i+3][j+3];
      unsigned d2 = grid[i][N-j-1] * grid[i+1][N-j-2] * grid[i+2][N-j-3] * grid[i+3][N-j-4];
      m = max(m, max(h, max(v, max(d1, d2))));
    }
  }
  printf("%u\n", m);

  return 0;
}

unsigned max(unsigned a, unsigned b)
{
  return a > b ? a : b;
}

Sample Output:

70600674

Flowchart:

C Programming Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a C programming to find the sum of all the primes below ten thousand.
Next: Write a C programming to find the sum of the even-valued terms from the terms in the Fibonacci sequence whose values do not exceed one million.