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C Exercises: Check if a given string is valid or not

C Programming Practice: Exercise-10 with Solution

Write a C programming to check if a given string is valid or not, the string contains the characters '(', ')', '{', '}', '[' and ']'. The string is valid if the open brackets must be closed by the same type of brackets and in correct order.

C Code:

#include <stdio.h>
#include <stdlib.h>
#include <stdbool.h>
static bool is_valid_Parentheses(char *s)
{
    int n = 0, cap = 100;
    char *tstack = malloc(cap);

    while (*s != '\0') {
        switch(*s) {
        case '(':
        case '[':
        case '{':
            if (n + 1 >= cap) {
                cap *= 2;
                tstack = realloc(tstack, cap);
            }
            tstack[n++] = *s;
            break;
        case ')':
            if (tstack[--n] != '(') return false;
            break;
        case ']':
            if (tstack[--n] != '[') return false;
            break;
        case '}':
            if (tstack[--n] != '{') return false;
            break;
        default:
            return false;
        }
        s++;
    }
    return n == 0;
}
int main(void)
  {
	//char **vbracket = "()[]{}";
	char **vbracket = "([)]";
	printf("%s\n", is_valid_Parentheses(vbracket) ? "true" : "false");
    return 0;
}

Sample Output:

false

Flowchart:

C Programming Flowchart: Check if a given string is valid or not

C Programming Code Editor:

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP