C Exercises: Find the largest element using Dynamic Memory Allocation
C Pointer : Exercise-9 with Solution
Write a program in C to find the largest element using Dynamic Memory Allocation.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
#include <stdlib.h>
int main()
{
int i,n;
float *element;
printf("\n\n Pointer : Find the largest element using Dynamic Memory Allocation :\n");
printf("-------------------------------------------------------------------------\n");
printf(" Input total number of elements(1 to 100): ");
scanf("%d",&n);
element=(float*)calloc(n,sizeof(float)); // Memory is allocated for 'n' elements
if(element==NULL)
{
printf(" No memory is allocated.");
exit(0);
}
printf("\n");
for(i=0;i<n;++i)
{
printf(" Number %d: ",i+1);
scanf("%f",element+i);
}
for(i=1;i<n;++i)
{
if(*element<*(element+i))
*element=*(element+i);
}
printf(" The Largest element is : %.2f \n\n",*element);
return 0;
}
Sample Output:
Pointer : Find the largest element using Dynamic Memory Allocation : ------------------------------------------------------------------------- Input total number of elements(1 to 100): 5 Number 1: 5 Number 2: 7 Number 3: 2 Number 4: 9 Number 5: 8 The Largest element is : 9.00
Flowchart:
C Programming Code Editor:
Have another way to solve this solution? Contribute your code (and comments) through Disqus.
Previous: Write a program in C to print all permutations of a given string using pointers.
Next: Write a program in C to Calculate the length of the string using a pointer.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
- New Content published on w3resource:
- HTML-CSS Practical: Exercises, Practice, Solution
- Java Regular Expression: Exercises, Practice, Solution
- Scala Programming Exercises, Practice, Solution
- Python Itertools exercises
- Python Numpy exercises
- Python GeoPy Package exercises
- Python Pandas exercises
- Python nltk exercises
- Python BeautifulSoup exercises
- Form Template
- Composer - PHP Package Manager
- PHPUnit - PHP Testing
- Laravel - PHP Framework
- Angular - JavaScript Framework
- Vue - JavaScript Framework
- Jest - JavaScript Testing Framework