C Exercises: Demonstrate the use of & and * operator
C Pointer : Exercise-3 with Solution
Write a program in C to demonstrate the use of &(address of) and *(value at address) operator.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int m=300;
float fx = 300.60;
char cht = 'z';
printf("\n\n Pointer : Demonstrate the use of & and * operator :\n");
printf("--------------------------------------------------------\n");
int *pt1;
float *pt2;
char *pt3;
pt1= &m;
pt2=&fx;
pt3=&cht;
printf ( " m = %d\n",m);
printf ( " fx = %f\n",fx);
printf ( " cht = %c\n",cht);
printf("\n Using & operator :\n");
printf("-----------------------\n");
printf ( " address of m = %p\n",&m);
printf ( " address of fx = %p\n",&fx);
printf ( " address of cht = %p\n",&cht);
printf("\n Using & and * operator :\n");
printf("-----------------------------\n");
printf ( " value at address of m = %d\n",*(&m));
printf ( " value at address of fx = %f\n",*(&fx));
printf ( " value at address of cht = %c\n",*(&cht));
printf("\n Using only pointer variable :\n");
printf("----------------------------------\n");
printf ( " address of m = %p\n",pt1);
printf ( " address of fx = %p\n",pt2);
printf ( " address of cht = %p\n",pt3);
printf("\n Using only pointer operator :\n");
printf("----------------------------------\n");
printf ( " value at address of m = %d\n",*pt1);
printf ( " value at address of fx= %f\n",*pt2);
printf ( " value at address of cht= %c\n\n",*pt3);
}
Sample Output:
Pointer : Demonstrate the use of & and * operator : -------------------------------------------------------- m = 300 fx = 300.600006 cht = z Using & operator : ----------------------- address of m = 0x7fff71cd0b38 address of fx = 0x7fff71cd0b3c address of cht = 0x7fff71cd0b37 Using & and * operator : ----------------------------- value at address of m = 300 value at address of fx = 300.600006 value at address of cht = z Using only pointer variable : ---------------------------------- address of m = 0x7fff71cd0b38 address of fx = 0x7fff71cd0b3c address of cht = 0x7fff71cd0b37 Using only pointer operator : ---------------------------------- value at address of m = 300 value at address of fx= 300.600006 value at address of cht= z
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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