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C Exercises: Demonstrate the use of & and * operator

C Pointer : Exercise-3 with Solution

Write a program in C to demonstrate the use of &(address of) and *(value at address) operator.

Pictorial Presentation:

C Exercises: Pictorial: Demonstrate the use of & and * operator.

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
  int m=300;
  float fx = 300.60;
  char cht = 'z';
  
   printf("\n\n Pointer : Demonstrate the use of & and * operator :\n"); 
   printf("--------------------------------------------------------\n");

 
  int *pt1;
  float *pt2;
  char *pt3;
  pt1= &m;
  pt2=&fx;
  pt3=&cht;
  printf ( " m = %d\n",m);
  printf ( " fx = %f\n",fx);
  printf ( " cht = %c\n",cht);
  printf("\n Using & operator :\n"); 
  printf("-----------------------\n");  
  printf ( " address of m = %p\n",&m);
  printf ( " address of fx = %p\n",&fx);
  printf ( " address of cht = %p\n",&cht);
  printf("\n Using & and * operator :\n"); 
  printf("-----------------------------\n"); 
  printf ( " value at address of m = %d\n",*(&m));
  printf ( " value at address of fx = %f\n",*(&fx));
  printf ( " value at address of cht = %c\n",*(&cht));
  printf("\n Using only pointer variable :\n"); 
  printf("----------------------------------\n"); 
  printf ( " address of m = %p\n",pt1);
  printf ( " address of fx = %p\n",pt2);
  printf ( " address of cht = %p\n",pt3);
  printf("\n Using only pointer operator :\n"); 
  printf("----------------------------------\n"); 
  printf ( " value at address of m = %d\n",*pt1);
  printf ( " value at address of fx= %f\n",*pt2);
  printf ( " value at address of cht= %c\n\n",*pt3);
}

Sample Output:

Pointer : Demonstrate the use of & and * operator :                                                          
--------------------------------------------------------                                                      
 m = 300                                                                                                      
 fx = 300.600006                                                                                              
 cht = z                                                                                                      
                                                                                                              
 Using & operator :                                                                                           
-----------------------                                                                                       
 address of m = 0x7fff71cd0b38                                                                                
 address of fx = 0x7fff71cd0b3c                                                                               
 address of cht = 0x7fff71cd0b37                                                                              
                                                                                                              
 Using & and * operator :                                                                                     
-----------------------------                                                                                 
 value at address of m = 300                                                                                  
 value at address of fx = 300.600006                                                                          
 value at address of cht = z              

 Using only pointer variable :                                                                                
----------------------------------                                                                            
 address of m = 0x7fff71cd0b38                                                                                
 address of fx = 0x7fff71cd0b3c                                                                               
 address of cht = 0x7fff71cd0b37                                                                              
                                                                                                              
 Using only pointer operator :                                                                                
----------------------------------                                                                            
 value at address of m = 300                                                                                  
 value at address of fx= 300.600006                                                                           
 value at address of cht= z 
 

Flowchart:

Flowchart: Demonstrate the use of & and * operator

C Programming Code Editor:

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Next: Write a program in C to add two numbers using pointers.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP