C Exercises: Sum of all elements in an array
C Pointer : Exercise-16 with Solution
Write a program in C to compute the sum of all elements in an array using pointers.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int arr1[10];
int i,n, sum = 0;
int *pt;
printf("\n\n Pointer : Sum of all elements in an array :\n");
printf("------------------------------------------------\n");
printf(" Input the number of elements to store in the array (max 10) : ");
scanf("%d",&n);
printf(" Input %d number of elements in the array : \n",n);
for(i=0;i<n;i++)
{
printf(" element - %d : ",i+1);
scanf("%d",&arr1[i]);
}
pt = arr1; // pt store the base address of array arr1
for (i = 0; i < n; i++) {
sum = sum + *pt;
pt++;
}
printf(" The sum of array is : %d\n\n", sum);
}
Sample Output:
Pointer : Sum of all elements in an array : ------------------------------------------------ Input the number of elements to store in the array (max 10) : 5 Input 5 number of elements in the array : element - 1 : 2 element - 2 : 3 element - 3 : 4 element - 4 : 5 element - 5 : 6 The sum of array is : 20
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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