C Exercises: Sort an array using pointer
C Pointer : Exercise-14 with Solution
Write a program in C to sort an array using Pointer.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int *a,i,j,tmp,n;
printf("\n\n Pointer : Sort an array using pointer :\n");
printf("--------------------------------------------\n");
printf(" Input the number of elements to store in the array : ");
scanf("%d",&n);
printf(" Input %d number of elements in the array : \n",n);
for(i=0;i<n;i++)
{
printf(" element - %d : ",i+1);
scanf("%d",a+i);
}
for(i=0;i<n;i++)
{
for(j=i+1;j<n;j++)
{
if( *(a+i) > *(a+j))
{
tmp = *(a+i);
*(a+i) = *(a+j);
*(a+j) = tmp;
}
}
}
printf("\n The elements in the array after sorting : \n");
for(i=0;i<n;i++)
{
printf(" element - %d : %d \n",i+1,*(a+i));
}
printf("\n");
}
Sample Output:
Pointer : Sort an array using pointer : -------------------------------------------- Input the number of elements to store in the array : 5 Input 5 number of elements in the array : element - 1 : 25 element - 2 : 45 element - 3 : 89 element - 4 : 15 element - 5 : 82 The elements in the array after sorting : element - 1 : 15 element - 2 : 25 element - 3 : 45 element - 4 : 82 element - 5 : 89
Flowchart :
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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