C Exercises: Explain whether a number is Keith or not
C Numbers: Exercise-37 with Solution
Write a program in C to check if a number is Keith or not(with explanation).
Test Data
Input a number : 1537
Sample Solution:
C Code:
# include <stdio.h>
# include <stdlib.h>
# include <stdbool.h>
# include <math.h>
int lenCount(int nm)
{ int ctr=0;
while(nm>0)
{
nm=nm/10;
ctr++;
}
return ctr;
}
int main()
{
int num1=0,arr1[10],num2=0,flg=0,i=0,sum=0,kk;
printf("\n\n Check whether a number is Keith or not: \n");
printf(" Sample Keith numbers: 197, 742, 1104, 1537, 2208, 2580, 3684, 4788, 7385..\n");
printf(" -----------------------------------------------------------------------\n");
printf(" Input a number : ");
scanf("%d",&num1);
num2=num1;
for(i=lenCount(num2)-1;i>=0;i--)
{
arr1[i]=num1 % 10;
num1/=10;
}
while(flg==0)
{
for(i=0;i<lenCount(num2);i++)
sum+=arr1[i];
if(sum==num2)
{
flg=1;
kk=1;
}
if(sum>num2)
{
flg=1;
kk=0;
}
for(i=0;i<lenCount(num2);i++)
{
printf(" %d",arr1[i]);
if(i!=lenCount(num2)-1)
{
arr1[i]=arr1[i+1];
printf(" + ");
}
else
{
arr1[i]=sum;
printf(" = %d",arr1[i]);
}
}
printf("\n");
sum=0;
}
if(kk==1)
{
printf(" The given number is a Keith Number.\n");
}
if(kk==0)
{
printf(" The given number is not a Keith Number.\n");
}
}
Sample Output:
Input a number : 1537 1 + 5 + 3 + 7 = 16 5 + 3 + 7 + 16 = 31 3 + 7 + 16 + 31 = 57 7 + 16 + 31 + 57 = 111 16 + 31 + 57 + 111 = 215 31 + 57 + 111 + 215 = 414 57 + 111 + 215 + 414 = 797 111 + 215 + 414 + 797 = 1537 The given number is a Keith Number.
Pictorial Presentation:
Flowchart:
C Programming Code Editor:
Contribute your code and comments through Disqus.
Previous: Write a program in C to check if a number is Keith or not.
Next: Write a C programming to check whether a given number with base b (2 <= b<= 10) is a Niven number or not.
What is the difficulty level of this exercise?
Test your Programming skills with w3resource's quiz.
C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
- New Content published on w3resource:
- HTML-CSS Practical: Exercises, Practice, Solution
- Java Regular Expression: Exercises, Practice, Solution
- Scala Programming Exercises, Practice, Solution
- Python Itertools exercises
- Python Numpy exercises
- Python GeoPy Package exercises
- Python Pandas exercises
- Python nltk exercises
- Python BeautifulSoup exercises
- Form Template
- Composer - PHP Package Manager
- PHPUnit - PHP Testing
- Laravel - PHP Framework
- Angular - JavaScript Framework
- Vue - JavaScript Framework
- Jest - JavaScript Testing Framework