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C Exercises: Check two numbers are Amicable numbers or not

C Numbers: Exercise-25 with Solution

Write a program in C to check two numbers are Amicable numbers or not.

Test Data
Input the 1st number : 1184
Input the 2nd number : 1210

Sample Solution:

C Code:

# include <stdio.h>
# include <stdlib.h>
# include <stdbool.h>
# include <math.h>


int ProDivSum(int n)
{
    int sum = 1;
    for (int i=2; i<=sqrt(n); i++)
    {
        if (n%i == 0)
        {
            sum += i;
            if (n/i != i)
                sum += n/i;
        }
    }
    return sum;
}
bool chkAmicable(int a,int b)
{
    return(ProDivSum(a) == b && ProDivSum(b) == a);
}
int main()
{
    int n, i, j, ctr,nm1,nm2;
 printf("\n\n Check whether two numbers are Amicable pairs or not: \n");
 printf("\n Sample: (220, 284), (1184, 1210), (2620, 2924).. \n");
 printf(" --------------------------------------------------------\n");	
		printf(" Input the 1st number : ");
		scanf("%d",&nm1);
		printf(" Input the 2nd number : ");
		scanf("%d",&nm2);  
   

      if( chkAmicable(nm1,nm2))
        printf(" The given numbers are an Amicable pair.\n");
    else
        printf(" The given numbers are not an Amicable pair.\n");
    return 0;
}

Sample Output: 

 Input the 1st number : 1184                                                                                  
 Input the 2nd number : 1210                                                                                  
 The given numbers are an Amicable pair.

Pictorial Presentation:

C programming: Check two numbers are Amicable numbers or not.

Flowchart:

Flowchart: Check two numbers are Amicable numbers or not

C Programming Code Editor:

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP