C Exercises: Check whether a number is Disarium or not

C Numbers: Exercise-15 with Solution

Write a program in C to check whether a number is Disarium or not.

Sample Solution:

C Code:

# include <stdio.h>
# include <math.h>
# include <stdlib.h>
# include <stdbool.h>


int DigiCount(int n)
{
    int ctr_digi = 0;
    int tmpx = n;
    while (tmpx)
    {
        tmpx = tmpx/10;
 
        ctr_digi++;
    }
    return ctr_digi;
}
bool chkDisarum(int n)
{
    int ctr_digi = DigiCount(n);
    int s = 0; 
    int x = n;
    int pr;
    while (x)
    {
        pr = x % 10;
        s = s + pow(pr, ctr_digi--);
        x = x/10;
    }
    return (s == n);
}
int main()
{

int dino;
printf("\n\n Check whether a number is Disarium Number or not: \n");
printf(" ------------------------------------------------------\n");
printf(" Input a number: ");
 scanf("%d",&dino);	
	
    if( chkDisarum(dino))
	printf(" The given number is a Disarium Number.\n");
    else
	printf(" The given number is not a Disarium Number.\n");
    return 0;
}

Sample Output:

 Input a number: 135                                                                                          
 The given number is a Disarium Number.

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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