C Exercises: Find the square root of a number using Babylonian method

C Programming Mathematics: Exercise-19 with Solution

Write a C program to find the square root of a number using Babylonian method.

Example 1:
Input: n = 50
Output: 7.071068
Example 2:
Input: n = 17
Output: 4.123106

Sample Solution:

C Code:

#include <stdio.h>

float square_Root(float n) 
{ 

   float a = n; 
        float b = 1; 
        double e = 0.000001; 
        while (a - b > e) { 
            a = (a + b) / 2; 
            b = n / a; 
        } 
   return a; 
} 
  
int main(void)
{ 
    int n = 50; 
    printf("Square root of %d is %f", n, square_Root(n)); 
    n = 17; 
    printf("\nSquare root of %d is %f", n, square_Root(n)); 
    return 0;    
}

Sample Output:

Square root of 50 is 7.071068
Square root of 17 is 4.123106

Flowchart:

C Programming Code Editor:

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