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C Exercises: Find the number of trailing zeroes in a given factorial

C Programming Mathematics: Exercise-10 with Solution

Write a C program to find the number of trailing zeroes in a given factorial.

Example 1:
Input: 4
Output: 0
Explanation: 4! = 24, no trailing zero.
Example 2:
Input: 6
Output: 1
Explanation: 6! = 720, one trailing zero.

Example:
Input:
n = 4
n = 5
Output:
Number of trailing zeroes of factorial 4 is 0
Number of trailing zeroes of factorial 5 is 1

Pictorial Presentation:

C Exercises: Find the number of trailing zeroes in a given factorial

Sample Solution:

C Code:

#include <stdio.h>

static int trailing_Zeroes(int n)
{
    int number = 0;
    while (n > 0) {
        number += n / 5;
         n /= 5;
    }
     return number;
}
int main(void)
{
    int n = 4;
    printf("\nNumber of trailing zeroes of factorial %d is %d ", n, trailing_Zeroes(n));
    n = 5;
    printf("\nNumber of trailing zeroes of factorial %d is %d ", n, trailing_Zeroes(n));
    return 0;
}

Sample Output:

Number of trailing zeroes of factorial 4 is 0 
Number of trailing zeroes of factorial 5 is 1 

Flowchart:

Flowchart: Find the number of trailing zeroes in a given factorial
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C Programming Code Editor:

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP