C Exercises: Check whether a given number is an armstrong number or not

C For Loop: Exercise-29 with Solution

Write a C program to check whether a given number is an armstrong number or not.

When the sum of the cube of the individual digits of a number is equal to that number, the number is called Armstrong number. For Example 153 is an Armstrong number because 153 = 1³+5³+3³.

Test Data :
Input a number: 153
Expected Output :
153 is an Armstrong number.

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Sample Solution:

C Code:

#include <stdio.h>

void main(){
    int num,r,sum=0,temp;

    printf("Input  a number: ");
    scanf("%d",&num);

    for(temp=num;num!=0;num=num/10){
         r=num % 10;
         sum=sum+(r*r*r);
    }
    if(sum==temp)
         printf("%d is an Armstrong number.\n",temp);
    else
         printf("%d is not an Armstrong number.\n",temp);

}

Sample Output:

Input  a number: 153                                                                                          
153 is an Armstrong number.   

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