C Exercises: Find the quadrant in which the coordinate point lies
C Conditional Statement: Exercise-9 with Solution
Write a C program to accept a coordinate point in a XY coordinate system and determine in which quadrant the coordinate point lies.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
int co1,co2;
printf("Input the values for X and Y coordinate : ");
scanf("%d %d",&co1,&co2);
if( co1 > 0 && co2 > 0)
printf("The coordinate point (%d,%d) lies in the First quandrant.\n",co1,co2);
else if( co1 < 0 && co2 > 0)
printf("The coordinate point (%d,%d) lies in the Second quandrant.\n",co1,co2);
else if( co1 < 0 && co2 < 0)
printf("The coordinate point (%d, %d) lies in the Third quandrant.\n",co1,co2);
else if( co1 > 0 && co2 < 0)
printf("The coordinate point (%d,%d) lies in the Fourth quandrant.\n",co1,co2);
else if( co1 == 0 && co2 == 0)
printf("The coordinate point (%d,%d) lies at the origin.\n",co1,co2);
}
Sample Output:
Input the values for X and Y coordinate : 7 9 The coordinate point (7,9) lies in the First quandrant.
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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