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C Exercises: Check whether a given year is a leap year or not

C Conditional Statement: Exercise-4 with Solution

Write a C program to find whether a given year is a leap year or not.

Pictorial Presentation:

Check whether a given year is a leap year or not

Sample Solution:

C Code:

#include <stdio.h>
void main()
{
    int chk_year;
 
    printf("Input a year :");
    scanf("%d", &chk_year);
    if ((chk_year % 400) == 0)
        printf("%d is a leap year.\n", chk_year);
    else if ((chk_year % 100) == 0)
        printf("%d is a not leap year.\n", chk_year);
    else if ((chk_year % 4) == 0)
        printf("%d is a leap year.\n", chk_year);
    else
        printf("%d is not a leap year \n", chk_year);
}

Sample Output:

Input a year :2016                                                                                            
2016 is a leap year.

Flowchart:

Flowchart: Check a given year is leap year or not

C Programming Code Editor:

Improve this sample solution and post your code through Disqus.

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Next: Write a C program to read the age of a candiadte and detrermine whether it is eligible for casting his/her own vote.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP