C Exercises: Check whether an alphabet is a vowel or consonant
C Conditional Statement: Exercise-17 with Solution
Write a C program to check whether an alphabet is a vowel or consonant.
Pictorial Presentation:
Sample Solution:
C Code:
#include <stdio.h>
void main()
{
char sing_ch;
printf("Input any alphabet : ");
scanf("%c", &sing_ch);
if(sing_ch=='a' || sing_ch=='e' || sing_ch=='i' || sing_ch=='o' || sing_ch=='u' || sing_ch=='A' || sing_ch=='E' || sing_ch=='I' || sing_ch=='O'
|| sing_ch=='U')
{
printf("The alphabet is a vowel.\n");
}
else if((sing_ch>='a' && sing_ch<='z') || (sing_ch>='A' && sing_ch<='Z'))
{
printf("The alphabet is a consonant.\n");
}
else
{
printf("The character is not an alphabet.\n");
}
}
Sample Output:
Input any alphabet : K The alphabet is a consonant.
Flowchart:
C Programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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