C Exercises: Find the angle between (12:00 to 11:59) the hour hand and the minute hand of a clock

C Basic Declarations and Expressions: Exercise-91 with Solution

Write a C program to find the angle between (12:00 to 11:59) the hour hand and the minute hand of a clock.
The hour hand and the minute hand is always among 0 degree and 180 degree. For example, when it's 12 o'clock, the angle of the two hands is 0 while 3:00 is 90 degree and 6:00 is 180 degree.

Sample Solution:

C Code:

#include <stdio.h>
#include <math.h>
#include <stdlib.h>

int main()
{
int h,m;
double angle;
const int num[13] = {0,30,60,90,120,150,180,210,240,270,300,330,0};
printf("Input hour(h) and minute(m) (separated by a space):\n");
scanf("%d %d",&h,&m);
angle = num[h] - m*5.5;
if (angle < 0)
angle = -angle;
if (angle > 180)
angle = 360 - angle;
if ( m < 10 )
printf("At %d:0%d the angle is %.1f degrees.\n",h,m,angle);
else
printf("The angle is %.1f degrees at %d:%d.\n",angle,h,m);
return 0;
}

Sample Output:

Input hour(h) and minute(m) (separated by a space):
The angle is -23076408.0 degrees at 0:4195776.

Flowchart:

C programming Code Editor:

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