C Exercises: Calculate the simple interest for the loan
C Basic Declarations and Expressions: Exercise-77 with Solution
Write a C program that accepts principal amount, rate of interest and days for a loan and calculate the simple interest for the loan, using the following formula.
interest = principal * rate * days / 365;
Sample Input: 10000
.1
365
0
Sample Solution:
C Code:
#include<stdio.h>
int main()
{
float principal_amt, rate_of_interest, days, interest;
const int yearInDays = 365;
printf( "Input loan amount (0 to quit): " );
scanf( "%f", &principal_amt );
while( (int)principal_amt != 0)
{
printf( "Input interest rate: " );
scanf( "%f", &rate_of_interest );
printf( "Input term of the loan in days: " );
scanf( "%f", &days );
interest = (principal_amt * rate_of_interest * days )/ yearInDays;
printf( "The interest amount is $%.2f\n", interest );
printf( "\n\nInput loan principal_amt (0 to quit): " );
scanf( "%f", &principal_amt );
}
return 0;
}
Sample Output:
Input loan amount (0 to quit): Input interest rate: Input term of the loan in days: The interest amount is $1000.00 Input loan principal_amt (0 to quit):
Flowchart:
C programming Code Editor:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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