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C Exercises: Print the alphabet set in decimal and character form

C Basic Declarations and Expressions: Exercise-70 with Solution

Write a C program to print the alphabet set in decimal and character form.

Pictorial Presentation:

C Programming: Print the alphabet set in decimal and character form.

Sample Solution:

C Code:

#include <stdio.h>
 #define N 10
int main() {
  char chr;
  printf("\n");
  for (chr = 65; chr <= 122; chr = chr + 1) {
    if (chr > 90 && chr < 97)
      continue;
    printf("[%2d-%c] ", chr, chr);
  }
  return 0;
}

Sample Output:

[65-A] [66-B] [67-C] [68-D] [69-E] [70-F] [71-G] [72-H] [73-I] [74-J] [75-K] [76-L] [77-M] [78-N] [79-O] [80-P] [81-Q] [82-R] [83-S] [84-T] [85-U] [86-V] [87-W] [88-X] [89-Y] [90-Z] [97-a] [98-b] [99-c] [100-d] [101-e] [102-f] [103-g] [104-h] [105-i] [106-j] [107-k] [108-l] [109-m] [110-n] [111-o] [112-p] [113-q] [114-r] [115-s] [116-t] [117-u] [118-v] [119-w] [120-x] [121-y] [122-z]

Flowchart:

C Programming Flowchart: Print the alphabet set in decimal and character form

C programming Code Editor:

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Next: Write a C program to copy a given string into another and count the number of characters copied.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP