C Exercises: Counts the number of positive numbers and print the average of all positive values
C Basic Declarations and Expressions: Exercise-28 with Solution
Write a C program that read 5 numbers and counts the number of positive numbers and print the average of all positive values.
Pictorial Presentation:
C Code:
#include <stdio.h>
int main() {
float numbers[5],total=0, avg;
int j, pctr=0;
printf("\nInput the first number: ");
scanf("%f", &numbers[0]);
printf("\nInput the second number: ");
scanf("%f", &numbers[1]);
printf("\nInput the third number: ");
scanf("%f", &numbers[2]);
printf("\nInput the fourth number: ");
scanf("%f", &numbers[3]);
printf("\nInput the fifth number: ");
scanf("%f", &numbers[4]);
for(j = 0; j < 5; j++) {
if(numbers[j] > 0)
{
pctr++;
total += numbers[j];
}
}
avg = total/pctr;
printf("\nNumber of positive numbers: %d", pctr);
printf("\nAverage value of the said positive numbers: %.2f", avg);
printf("\n");
return 0;
}
Sample Output:
Input the first number: 5 Input the second number: 8 Input the third number: 10 Input the fourth number: -5 Input the fifth number: 25 Number of positive numbers: 4 Average value of the said positive numbers: 12.00
Flowchart:
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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