C Exercises: Reads an integer between 1 and 12 and print the month of the year in English
C Basic Declarations and Expressions: Exercise-25 with Solution
Write a C program that reads an integer between 1 and 12 and print the month of the year in English.
Pictorial Presentation:
C Code:
#include <stdio.h>
int main() {
int mno;
printf("\nInput a number between 1 to 12 to get the month name: ");
scanf("%d", &mno);
switch(mno) {
case 1 : printf("January\n"); break;
case 2 : printf("February\n"); break;
case 3 : printf("March\n"); break;
case 4 : printf("April\n"); break;
case 5 : printf("May\n"); break;
case 6 : printf("June\n"); break;
case 7 : printf("July\n"); break;
case 8 : printf("August\n"); break;
case 9 : printf("September\n"); break;
case 10 : printf("October\n"); break;
case 11 : printf("November\n"); break;
case 12 : printf("December\n"); break;
default : printf("Input a number between 1 to 12.");
}
return 0;
}
Sample Output:
Input a number between 1 to 12 to get the month name: 8 August
Flowchart:
C Programming Code Editor:
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Next: Write a C program that prints all even numbers between 1 and 50 (inclusive).
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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