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C Exercises: Reads an integer between 1 and 12 and print the month of the year in English

C Basic Declarations and Expressions: Exercise-25 with Solution

Write a C program that reads an integer between 1 and 12 and print the month of the year in English.

Pictorial Presentation:

C Programming: Reads an integer between 1 and 12 and print the month of the year in English

C Code:

#include <stdio.h>

int main() {
	int mno;
	printf("\nInput a number between 1 to 12 to get the month name: ");
	scanf("%d", &mno);
	switch(mno) {
		case 1 : printf("January\n"); break;
		case 2 : printf("February\n"); break;
		case 3 : printf("March\n"); break;
		case 4 : printf("April\n"); break;
		case 5 : printf("May\n"); break;
		case 6 : printf("June\n"); break;
		case 7 : printf("July\n"); break;
		case 8 : printf("August\n"); break;
		case 9 : printf("September\n"); break;
		case 10 : printf("October\n"); break;
		case 11 : printf("November\n"); break;
		case 12 : printf("December\n"); break;
		default : printf("Input a number between 1 to 12.");
	}
	return 0;
}

Sample Output:

Input a number between 1 to 12 to get the month name: 8                
August

Flowchart:

C Programming Flowchart: Reads an integer between 1 and 12 and print the month of the year in English

C Programming Code Editor:


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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP