C Exercises: Read an amount and break the amount into smallest possible number of bank notes

C Basic Declarations and Expressions: Exercise-16 with Solution

Write a C program to read an amount (integer value) and break the amount into smallest possible number of bank notes.
Note: The possible banknotes are 100, 50, 20, 10, 5, 2 and 1.

C Code:

#include <stdio.h>
int main() {
	int amt, total;
	printf("Input the amount: ");
	scanf("%d",&amt);
	
	total = (int)amt/100;
	
	printf("There are: ");
	
	printf("\n%d Note(s) of 100.00\n", total);
	
	amt = amt-(total*100);
	
	total = (int)amt/50;
	
	printf("%d Note(s) of 50.00\n", total);
	
	amt = amt-(total*50);
	
	total = (int)amt/20;
	
	printf("%d Note(s) of 20.00\n", total);
	
	amt = amt-(total*20);
	
	total = (int)amt/10;
	
	printf("%d Note(s) of 10.00\n", total);
	
	amt = amt-(total*10);
	
	total = (int)amt/5;
	
	printf("%d Note(s) of 5.00\n", total);
	
	amt = amt-(total*5);
	
	total = (int)amt/2;
	
	printf("%d Note(s) of 2.00\n", total);
	
	amt = amt-(total*2);
	
	total = (int)amt/1;
	
	printf("%d Note(s) of 1.00\n", total);
	
	return 0;
}

Sample Output:

Input the amount: 375                                                  
There are:                                                             
3 Note(s) of 100.00                                                    
1 Note(s) of 50.00                                                     
1 Note(s) of 20.00                                                     
0 Note(s) of 10.00                                                     
1 Note(s) of 5.00                                                      
0 Note(s) of 2.00                                                      
0 Note(s) of 1.00

Flowchart:

C Programming Code Editor:

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