C Exercises: Sum of all numerical values (positive integers) embedded in a sentence
C Basic Declarations and Expressions: Exercise-145 with Solution
Write a C program to sum of all numerical values (positive integers) embedded in a sentence.
Input:
Sentences with positive integers are given over multiple lines. Each line is a character string containing one-byte alphanumeric characters, symbols, spaces, or an empty line. However the input is 80 characters or less per line and the sum is 10,000 or less
Sample Solution:
C Code:
#include <stdio.h>
#include <stdlib.h>
char text[128];
int main(void) {
int i, j, k;
int result = 0;
char temp[8];
printf("Input Sentences with positive integers:\n");
scanf("%s", text);
i = 0;
while (text[i]) {
for (;
(text[i] < '0' || '9' < text[i]) && text[i]; i++);
if ('0' <= text[i] && text[i] <= '9') {
for (j = 0;
'0' <= text[i] && text[i] <= '9'; j++, i++) {
temp[j] = text[i];
}
temp[j] = '\0';
result += atoi(temp);
}
}
printf("\nSum of all numerical values embedded in a sentence:\n");
printf("%d\n", result);
return 0;
}
Sample Output:
Input Sentences with positive integers: 5littleJackand2mouse. Sum of all numerical values embedded in a sentence: 7
Flowchart:
C programming Code Editor:
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Next: Write a C program to extract words of 3 to 6 characters length from a given sentence not more than 1024 characters.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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