C Exercises: Find heights of the top three building in descending order from eight given buildings
C Basic Declarations and Expressions: Exercise-132 with Solution
Write a Java program to find heights of the top three building in descending order from eight given buildings.
Input:
0 <= height of building (integer) <= 10,000
Sample Solution:
C Code:
#include <stdio.h>
int main(){
int heights[10],i,j,h,max_heights;
printf("Input heights(integer values) of the top eight buildings:\n");
for(i=0;i<8;i++)
{ scanf("%d",&heights[i]); }
for(i=0;i<8;i++){
max_heights=i;
for(j=i;j<8;j++){
if(heights[j]>heights[max_heights]){ max_heights=j ;}
}
h=heights[max_heights];
heights[max_heights]=heights[i];
heights[i]=h;
}
printf("\nHeights of the top three building:\n");
printf("%d\n%d\n%d\n",heights[0],heights[1],heights[2]);
return 0;
}
Sample Output:
Input heights(integer values) of the top eight buildings: 25 15 45 22 35 18 95 65 Heights of the top three building: 95 65 45
Flowchart:
C programming Code Editor:
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Previous: Write a C program that accepts two strings and check whether the second string present in the last part of the first string.
Next: Write a C program to calculate the sum of two given integers and count the number of digits of the sum value.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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