C Exercises: Array fill, replace each subsequent position of the array by the double value of the previous
C Basic Declarations and Expressions: Exercise-125 with Solution
Write a C program that reads an array of integers (length 7), and replace the first element of the array by a give number and replace each subsequent position of the array by the double value of the previous.
Sample Solution:
C Code:
#include <stdio.h>
int main ()
{
int array_nums[7], i, x, k;
printf("Input the first element of the array:\n");
scanf("%d", &x);
for (k = 0, i = x; k < 7; i *= 2, k++)
{
array_nums[k] = i;
}
printf("\nArray elements:\n");
for (i = 0; i < 7; i++)
{
printf("array_nums[%d] = %d\n", i, array_nums[i]);
}
}
Sample Output:
Input the first element of the array: 5 Array elements: array_nums[0] = 5 array_nums[1] = 10 array_nums[2] = 20 array_nums[3] = 40 array_nums[4] = 80 array_nums[5] = 160 array_nums[6] = 320
Flowchart:
C programming Code Editor:
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Previous: Write a C program that reads an array of integers (length 7), replace every negative or null element by 1 and print the array elements.
Next: Write a C program that reads an array (length 7) and print all array positions that store a value less or equal to 0.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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