C Exercises: Read an integer and compute all its divisors

Last update on May 27 2022 12:13:52 (UTC/GMT +8 hours)

C Basic Declarations and Expressions: Exercise-121 with Solution

Write a C program that reads an integer and find all the divisors of the said integer.

Sample Solution:

C Code:

#include <stdio.h>
int main ()
{
  int i, n;
  printf("Input a number (integer value):\n");
  scanf("%d", &n);
  printf("\nAll positive divisors of %d \n",n);
  for (i = 1; i <= n; i++)
  {

    if (n % i == 0)
    {

      printf("%d\n", i);

    }
  }
}

Sample Output:

Input a number (integer value):
35

All positive divisors of 35
1
5
7
35

Flowchart:

C programming Code Editor:

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Previous: Write a C program to print a sequence from 1 to a given (integer) number, insert a comma between these numbers, there will be no comma after the last character.
Next: Write a C program that reads two integers m, n and compute the sum of n even numbers starting from m.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP