C Exercises: Sum of all even values between two input integers, exclusive input values
C Basic Declarations and Expressions: Exercise-114 with Solution
Write a C program that accepts two integers values and calculate the sum of all even values between them, exclusive input values.
Sample Solution:
C Code:
#include <stdio.h>
int main () {
int y, i, z;
int l, m, n, ctr1 = 0, ctr2 = 0;
printf("Input two numbers (integer values):\n");
scanf("%d %d", &m, &n);
ctr1 = 0;
printf("\nSum of all even values between %d and %d\n",m,n);
if (m > n){
for (l = n + 1; l < m; l++){
if (l % 2 == 0){
ctr1 += l;
}
}
printf("%d\n", ctr1);
}
else{
for (l = m + 1; l < n; l++){
if (l % 2 == 0){
ctr2 += l;
}
}
printf("%d\n", ctr2);
}
}
Sample Output:
Input two numbers (integer values): 25 45 Sum of all even values between 25 and 45 350
Sample Output:
Input two numbers (integer values): 27 13 Sum of all even values between 27 and 13 140
Flowchart:
C programming Code Editor:
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Previous: Write a C program to create and print the sequence of the following example.
Next: Write a C program that accepts a pair of numbers from the user and print the sequence from the lowest to highest number. Also, print the average value of the sequence.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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