C Exercises: Check if a given array of integers contains no 3 or a 5

C-programming basic algorithm: Exercise-59 with Solution

Write a C program to check if a given array of integers contains no 3 or a 5.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
    int arr_size;
    int array1[] = {1, 5, 5, 5, 5};
    arr_size = sizeof(array1)/sizeof(array1[0]);
    printf("%d",test(array1, arr_size));
    int array2[] = {3, 3, 3, 3 };
    arr_size = sizeof(array2)/sizeof(array2[0]);
    printf("\n%d",test(array2, arr_size));
    int array3[] = {3, 3, 3, 5, 5, 5};
    arr_size = sizeof(array3)/sizeof(array3[0]);
    printf("\n%d",test(array3, arr_size));
    int array4[] = {1, 6, 8, 10};
    arr_size = sizeof(array3)/sizeof(array4[0]);
    printf("\n%d",test(array4, arr_size));
  }    
  int test(int nums[], int arr_size)
         {
           int three = 0, five = 0;
            for (int i = 0; i < arr_size; i++)
            {
                if (nums[i] == 3) three++;
                if (nums[i] == 5) five++;
             if (three && five) return 0;
            }
            return 1;
         }   

Sample Output:

1
1
0
1

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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