C Exercises: Create a new array from two given array of integers of length 3

C-programming basic algorithm: Exercise-47 with Solution

Write a C program to create a new array from two given array of integers of length 3.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
    int new_arr_size = 6;
    int arr_size1, arr_size2;
    int nums1[] = {10, 20, 30};
    int nums2[] = {40, 50, 60};
    arr_size1 = sizeof(nums1)/sizeof(nums1[0]);
    arr_size2 = sizeof(nums2)/sizeof(nums2[0]);
    printf("Elements in original array1 are: ");  
    print_array(nums1, arr_size1);
    printf("Elements in original array2 are: "); 
    print_array(nums2, arr_size2);
    int result[] = { nums1[0], nums1[1], nums1[2], nums2[0], nums2[1], nums2[2] };
    printf("New array: ");  
    print_array(result, new_arr_size);        
 }  
 print_array(int parray[], int size)
  {
   int i;      
   for( i=0; i<size-1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
   printf("%d ", parray[i]);  
   printf("\n");   
  } 

Sample Output:

Elements in original array1 are: 10, 20, 30 
Elements in original array2 are: 40, 50, 60 
New array: 10, 20, 30, 40, 50, 60

Pictorial Presentation:

Flowchart:

C Programming Code Editor:

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