Please note, this is a STATIC archive of website www.w3resource.com from 19 Jul 2022, cach3.com does not collect or store any user information, there is no "phishing" involved.
w3resource

C Exercises: Check whether a given array of integers of length 2, contains 15 or 20

C-programming basic algorithm: Exercise-41 with Solution

Write a C program to check whether a given array of integers of length 2, contains 15 or 20.

C Code:

#include <stdio.h>
#include <stdlib.h>
int main(void){
    int arr_size;
    int array1[] = {12, 20};
    printf("%d",test(array1));
    int array2[] = {14, 15};
    printf("\n%d",test(array2));
    int array3[] =  {11, 21};
    printf("\n%d",test(array3));
    }       
    int test(int nums[])
         {
             return nums[0] == 12 || nums[0] == 15 || nums[1] == 12 || nums[1] == 15;
        }

Sample Output:

1
1
0

Pictorial Presentation:

C Programming Algorithm: Check whether a given array of integers of length 2, contains 15 or 20

Flowchart:

C Programming Algorithm Flowchart: Check whether a given array of integers of length 2, contains 15 or 20

C Programming Code Editor:

Contribute your code and comments through Disqus.

Previous: Write a C program to create a new array taking the first and last elements of a given array of integers and length 1 or more.
Next: Write a C program to check whether a given array of integers of length 2, does not contain 15 or 20.

What is the difficulty level of this exercise?

Test your Programming skills with w3resource's quiz.



C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP