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C Exercises: Create a new array containing the middle elements from the two given arrays of integers, each length 5

C-programming basic algorithm: Exercise-39 with Solution

Write a C program to create a new array containing the middle elements from the two given arrays of integers, each length 5.

C Code:

#include <stdio.h>
#include <stdlib.h>s

int main(void){ 
    int arr_size;
    int a1[] = {10, 20, -30, -40, 30 };
    int a2[] = {10, 20, 30, 40, 30};
    int arr_size1 = sizeof(a1)/sizeof(a1[0]);
    int arr_size2 = sizeof(a2)/sizeof(a2[0]);
    printf("Elements in original array are:\n");  
    print_array(a1, arr_size1);
    print_array(a2, arr_size2);  
    int result[] = { a1[2], a2[2]  };
    arr_size = sizeof(result)/sizeof(result[0]);
    printf("Elements in new array are: ");  
    print_array(result, arr_size);
    }     
 print_array(int parray[], int size)
  {
   int i;      
   for( i=0; i<size-1; i++)  
    {  
        printf("%d, ", parray[i]);  
    } 
   printf("%d ", parray[i]);  
   printf("\n");   
  }

Sample Output:

Elements in original array are:
10, 20, -30, -40, 30 
10, 20, 30, 40, 30 
Elements in new array are: -30, 30

Pictorial Presentation:

C Programming Algorithm: Create a new array containing the middle elements from the two given arrays of integers, each length 5

Flowchart:

C Programming Algorithm Flowchart: Create a new array containing the middle elements from the two given arrays of integers, each length 5

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP