C Exercises: Check a given array of integers of length 1 or more and return true if the first element and the last element are equal in the given array
C-programming basic algorithm: Exercise-34 with Solution
Write a C program to check a given array of integers of length 1 or more and return true if the first element and the last element are equal in the given array.
C Code:
#include <stdio.h>
#include <stdlib.h>
int main(void){
int arr_size;
int array1[] = {1, 1, 2, 2, 1};
arr_size = sizeof(array1)/sizeof(array1[0]);
printf("%d",test(array1, arr_size));
int array2[] = {1, 1, 2, 1, 2, 3};
arr_size = sizeof(array2)/sizeof(array2[0]);
printf("\n%d",test(array2, arr_size));
int array3[] = { 12, 24, 35, 55 };
arr_size = sizeof(array3)/sizeof(array3[0]);
printf("\n%d",test(array3, arr_size));
}
int test(int nums[], int arr_size)
{
return arr_size > 0 && nums[0] == nums[arr_size - 1];
}
Sample Output:
1 0 0
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Flowchart:
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Previous: Write a C program to check three given integers (small, medium and large) and return true if the difference between small and medium and the difference between medium and large is same.
Next: Write a C program to check two given arrays of integers of length 1 or more and return true if they have the same first element or they have the same last element.
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C Programming: Tips of the Day
Static variable inside of a function in C
The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().
The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.
The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().
Ref : https://bit.ly/3fOq7XP
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