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C Exercises: Check two given integers and return the value whichever value is nearest to 13 without going over

C-programming basic algorithm: Exercise-32 with Solution

Write a C program to check two given integers and return the value whichever value is nearest to 13 without going over. Return 0 if both numbers go over.

C Code:

#include <stdio.h>
#include <stdlib.h>

int main(void){    
    printf("%d",test(4, 5));
    printf("\n%d",test(7, 12));
    printf("\n%d",test(10, 13));
    printf("\n%d",test(17, 33));
    }       
   int test(int x, int y)
         {
            if (x > 13 && y > 13) return 0;
            if (x <= 13 && y > 13) return x;
            if (x <= 13 && y > 13) return y;
            return x > y ? x : y;
         }

Sample Output:

5
12
13
0

Pictorial Presentation:

C Programming Algorithm: Check two given integers and return the value whichever value is nearest to 13 without going over

Flowchart:

C Programming Algorithm Flowchart: Check two given integers and return the value whichever value is nearest to 13 without going over

C Programming Code Editor:

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Previous: Write a C program to compute the sum of the three given integers. However, if any of the values is in the range 10..20 inclusive then that value counts as 0, except 13 and 17.
Next: Write a C program to check three given integers (small, medium and large) and return true if the difference between small and medium and the difference between medium and large is same.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP