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C Exercises: Check two given integers, each in the range 10..99. Return true if a digit appears in both numbers, such as the 3 in 13 and 33

C-programming basic algorithm: Exercise-28 with Solution

Write a C program to check two given integers, each in the range 10..99. Return true if a digit appears in both numbers, such as the 3 in 13 and 33.

C Code:

#include <stdio.h>
#include <stdlib.h>

int main(void){    
    printf("%d",test(11, 21));
    printf("\n%d",test(11, 20));
    printf("\n%d",test(10, 10));
    }       
    int test(int x, int y)
         {
            return x / 10 == y / 10 || x / 10 == y % 10 || x % 10 == y / 10 || x % 10 == y % 10;
         }

Sample Output:

1
0
1

Pictorial Presentation:

C Programming Algorithm: Check two given integers, each in the range 10..99. Return true if a digit appears in both  numbers, such as the 3 in 13 and 33

Flowchart:

C Programming Algorithm Flowchart: Check two given integers, each in the range 10..99. Return true if a digit appears in both  numbers, such as the 3 in 13 and 33

C Programming Code Editor:

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Previous: Write a C program to find the larger from two given integers. However if the two integers have the same remainder when divided by 5, then the return the smaller integer. If the two integers are the same, return 0.
Next: Write a C program to compute the sum of three given integers. If the two values are same return the third value.

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C Programming: Tips of the Day

Static variable inside of a function in C

The scope of variable is where the variable name can be seen. Here, x is visible only inside function foo().

The lifetime of a variable is the period over which it exists. If x were defined without the keyword static, the lifetime would be from the entry into foo() to the return from foo(); so it would be re-initialized to 5 on every call.

The keyword static acts to extend the lifetime of a variable to the lifetime of the programme; e.g. initialization occurs once and once only and then the variable retains its value - whatever it has come to be - over all future calls to foo().

Ref : https://bit.ly/3fOq7XP